(x^2+x-56)/(x^2-x-42)=0

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Solution for (x^2+x-56)/(x^2-x-42)=0 equation: 


D( x )

x^2-x-42 = 0

x^2-x-42 = 0

x^2-x-42 = 0

x^2-x-42 = 0

DELTA = (-1)^2-(-42*1*4)

DELTA = 169

DELTA > 0

x = (169^(1/2)+1)/(1*2) or x = (1-169^(1/2))/(1*2)

x = 7 or x = -6

x in (-oo:-6) U (-6:7) U (7:+oo)

(x^2+x-56)/(x^2-x-42) = 0

x^2+x-56 = 0

x^2+x-56 = 0

DELTA = 1^2-(-56*1*4)

DELTA = 225

DELTA > 0

x = (225^(1/2)-1)/(1*2) or x = (-225^(1/2)-1)/(1*2)

x = 7 or x = -8

(x+8)*(x-7) = 0

x^2-x-42 = 0

x^2-x-42 = 0

DELTA = (-1)^2-(-42*1*4)

DELTA = 169

DELTA > 0

x = (169^(1/2)+1)/(1*2) or x = (1-169^(1/2))/(1*2)

x = 7 or x = -6

(x+6)*(x-7) = 0

((x+8)*(x-7))/((x+6)*(x-7)) = 0

( x+8 )

x+8 = 0 // - 8

x = -8

( x-7 )

x-7 = 0 // + 7

x = 7

x in { 7} 

x = -8

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